Tower

The top of the tower is a regular hexagonal pyramid with base edge 8 meters long and a height 5 meters. How many m2 of the sheet is required to cover the top of the tower if we count 8% of the sheet waste?

Correct result:

S =  221 m2

Solution:

 a=8 m v=5 m  a2(a/2)2=v22 v2=a32=6.928 m  h2=v2+v22 h=52+6.9282=8.544 m  S1=12ah=1288.544=34.18 m2  S=6S1(1+8100)=634.181.08=221 m2



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