Tower Sheet Metal Coverage

The tower has the shape of a regular four-sided pyramid with a base edge of 0.8 m. The height of the tower is 1.2 meters. How many square meters of sheet metal is needed for coverage if we count eight percent for joints and overlap?

Final Answer:

S =  2.1858 m²

Step-by-step explanation:

$$\begin{gathered} a=0.8\text{m} \\ h=1.2\text{m} \\ {h}_2=\sqrt{(a/2{)}^2+h^2}=\sqrt{(0.8/2{)}^2+1.2^2}\doteq 1.2649\text{m} \\ {S}_1=\frac{a\cdot h_2}{2}=\frac{0.8\cdot 1.2649}{2}\doteq 0.506{\text{m}}^2 \\ q=100\%+8\%=1+\frac{8}{100}=1.08 \\ S=4\cdot S_1\cdot q=4\cdot 0.506\cdot 1.08=2.1858{\text{m}}^2 \end{gathered}$$

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