Surface of pyramid

A regular quadrilateral pyramid has the height of the sidewall equal to the length of the edge of the base. The area of the sidewall is 32 cm2. What is the surface of the pyramid?

Correct answer:

S =  192 cm2

Step-by-step explanation:

S2=32 cm2 S2 = 2a h a=h S2 = a2/2 a=2 S2=2 32=8 cm S1=a2=82=64 cm2  S=4 S2+S1=4 32+64=192 cm2

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