Quadrilateral 44561

The regular quadrilateral pyramid has a volume of 212 m3 and a base edge a = 7.2 m. Calculate the surface area and height of the pyramid.

Correct answer:

h =  12.2685 m
S =  235.9554 m2

Step-by-step explanation:

V=212 m3 a=7.2 m  S1=a2=7.22=251296=51.84 m2  V=31S1 h  h=S13 V=51.843 212=1081325 m=12.2685 m
h2=h2+(a/2)2=12.26852+(7.2/2)212.7858 m2 S2=2a h2=27.2 12.785846.0289 m2  S=S1+4 S2=51.84+4 46.0289=235.9554 m2



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