Quadrilateral pyramid

We have a regular quadrilateral pyramid with a base edge a = 10 cm and a height v = 7 cm.
1/base area
2/casing area
3/pyramid surface
4/volume of the pyramid

Correct answer:

S1 =  100 cm2
S3 =  172.0465 cm2
S =  272.0465 cm2
V =  233.3333 cm3

Step-by-step explanation:

a=10 cm v=7 cm  S1=a2=102=100 cm2
h2=v2+(a/2)2=72+(10/2)2=74 cm8.6023 cm S2=a h2/2=10 8.6023/2=5 74 cm243.0116 cm2 S3=4 S2=4 43.0116=20 74=172.0465 cm2
S=S1+S3=100+172.0465=272.0465 cm2
V=31 S1 v=31 100 7=3700 cm3=233.3333 cm3

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