Quadrilateral pyramid

A regular quadrilateral pyramid has a volume of 24 dm3 and a base edge a = 4 dm.
a/height of the pyramid
b/sidewall height
c/surface of the pyramid

Correct answer:

h =  4.5 dm
h2 =  4.9244 dm
S =  55.3954 dm2

Step-by-step explanation:

V=24 dm3 a=4 dm  S1=a2=42=16 dm2  V=31S1 h  h=S13 V=163 24=29 dm=4.5 dm
h2=h2+(a/2)2=4.52+(4/2)2=4.9244 dm
S2=2a h2=24 4.9244=97 dm29.8489 dm2  S=S1+4 S2=16+4 9.8489=55.3954 dm2

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