Hexagonal pyramid

Regular hexagonal pyramid has dimensions: length edge of the base a = 1.8 dm and the height of the pyramid = 2.4 dm. Calculate the surface area and volume of a pyramid.

Result

S =  23.872 dm2
V =  6.734 dm3

Solution:

a=1.8 dm v=2.4 dm h1=a 3/2=1.8 3/21.5588 dm h2=v2+h12=2.42+1.558822.8618 dm  S1=a h1/2=1.8 1.5588/21.403 dm2 S2=6 S1=6 1.4038.4178 dm2 S3=a h2/2=1.8 2.8618/22.5756 dm2 S=S2+6 S3=8.4178+6 2.575623.871623.872 dm2a=1.8 \ \text{dm} \ \\ v=2.4 \ \text{dm} \ \\ h_{ 1 }=a \cdot \ \sqrt{ 3 }/2=1.8 \cdot \ \sqrt{ 3 }/2 \doteq 1.5588 \ \text{dm} \ \\ h_{ 2 }=\sqrt{ v^2+h_{ 1 }^2 }=\sqrt{ 2.4^2+1.5588^2 } \doteq 2.8618 \ \text{dm} \ \\ \ \\ S_{ 1 }=a \cdot \ h_{ 1 }/2=1.8 \cdot \ 1.5588/2 \doteq 1.403 \ \text{dm}^2 \ \\ S_{ 2 }=6 \cdot \ S_{ 1 }=6 \cdot \ 1.403 \doteq 8.4178 \ \text{dm}^2 \ \\ S_{ 3 }=a \cdot \ h_{ 2 }/2=1.8 \cdot \ 2.8618/2 \doteq 2.5756 \ \text{dm}^2 \ \\ S=S_{ 2 } + 6 \cdot \ S_{ 3 }=8.4178 + 6 \cdot \ 2.5756 \doteq 23.8716 \doteq 23.872 \ \text{dm}^2
V=13 S2 v=13 8.4178 2.46.73426.734 dm3V=\dfrac{ 1 }{ 3 } \cdot \ S_{ 2 } \cdot \ v=\dfrac{ 1 }{ 3 } \cdot \ 8.4178 \cdot \ 2.4 \doteq 6.7342 \doteq 6.734 \ \text{dm}^3



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