Hexagonal pyramid

Calculate the volume and surface area of a regular hexagonal pyramid with a base edge a = 30 m and a side edge b = 50 m.

Correct result:

V =  31176.9145 m3
S =  6630.995 m2

Solution:

a=30 m b=50 m n=6  S0=34⋅ a2=34⋅ 302=225 3 m2≐389.7114 m2 S1=n⋅ S0=6⋅ 389.7114=1350 3 m2≐2338.2686 m2  h=b2−a2=502−302=40 m  V=13⋅ S1⋅ h=13⋅ 2338.2686⋅ 40=31176.9145 m3=3.118⋅104 m3

Try calculation via our triangle calculator.

o=n⋅ a=6⋅ 30=180 m  h2=b2−(a/2)2=502−(30/2)2=5 91 m≐47.697 m  S2=a⋅ h22=30⋅ 47.6972=75 91 m2≐715.4544 m2  S=S1+n⋅ S2=2338.2686+6⋅ 715.4544=6630.995 m2

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