Hexagonal pyramid

Calculate a regular hexagonal pyramid's volume and surface area with a base edge a = 30 m and a side edge b = 50 m.

Correct answer:

V =  31176.9145 m3
S =  6630.995 m2

Step-by-step explanation:

a=30 m b=50 m n=6  S0​=43​​⋅ a2=43​​⋅ 302=225 3​ m2≐389.7114 m2 S1​=n⋅ S0​=6⋅ 389.7114=1350 3​ m2≐2338.2686 m2  h=b2−a2​=502−302​=40 m  V=31​⋅ S1​⋅ h=31​⋅ 2338.2686⋅ 40=31176.9145 m3

Try calculation via our triangle calculator.

o=n⋅ a=6⋅ 30=180 m  h2​=b2−(a/2)2​=502−(30/2)2​=5 91​ m≐47.697 m  S2​=2a⋅ h2​​=230⋅ 47.697​=75 91​ m2≐715.4544 m2  S=S1​+n⋅ S2​=2338.2686+6⋅ 715.4544=6630.995 m2

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solid geometryplanimetricsUnits of physical quantitiesGrade of the word problem

 
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