Quadrilateral 6116

The area of a regular quadrilateral pyramid's mantle is equal to twice its base's area. Calculate the pyramid's surface if the length of the base edge is 20 dm.

Correct answer:

S =  1200 dm2

Step-by-step explanation:

a=20 dm S1=a2=202=400 dm2 S2=2 S1=2 400=800 dm2  S=S1+S2=400+800=1200 dm2



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