Quadrilateral pyramid

In a regular quadrilateral pyramid, the side edge is e = 7 dm and the diagonal of the base is 50 cm. Calculate the pyramid shell area.

Correct result:

S =  47.8931 dm2

Solution:

e=7 dm u=50 cm→ dm=50/10  dm=5 dm  a=u/2=5/2≐3.5355 dm  h2+(a/2)2=e2 h=e2−(a/2)2=72−(3.5355/2)2≐6.7731 dm  S1=a⋅ h2=3.5355⋅ 6.77312≐11.9733 dm2  S=4⋅ S1=4⋅ 11.9733=47.8931 dm2

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