Quadrilateral pyramid

In a regular quadrilateral pyramid, the side edge is e = 7 dm, and the diagonal of the base is 50 cm. Calculate the pyramid shell area.

Correct answer:

S =  47.8931 dm2

Step-by-step explanation:

e=7 dm u=50 cm dm=50:10  dm=5 dm  a=u/2=5/23.5355 dm  h2 + (a/2)2 = e2 h=e2(a/2)2=72(3.5355/2)26.7731 dm  S1=2a h=23.5355 6.773111.9733 dm2  S=4 S1=4 11.9733=47.8931 dm2

Did you find an error or inaccuracy? Feel free to write us. Thank you!

Tips for related online calculators
See also our trigonometric triangle calculator.

You need to know the following knowledge to solve this word math problem:

We encourage you to watch this tutorial video on this math problem: video1

Related math problems and questions: