Quadrilateral 83254

What is the volume of a regular quadrilateral pyramid if its base edge a = √18 cm and side edge b = 5 cm?

Correct answer:

V =  24 cm3

Step-by-step explanation:

a=18=3 2 cm4.2426 cm b=5 cm  S1=a2=4.24262=18 cm2  a2+a2 = u2  u=2 a=2 4.2426=6 cm  b2 = h2 + (u/2)2  h=b2(u/2)2=52(6/2)2=4 cm  V=31 S1 h=31 18 4=24 cm3



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