Quadrangular pyramid

Given is a regular quadrangular pyramid with a square base. The body height is 30 cm, and volume V = 1000 cm³. Calculate its side and its surface area.

Final Answer:

a =  10 cm
S =  708.2763 cm²

Step-by-step explanation:

$$\begin{gathered} h=30\text{cm} \\ V=1000{\text{cm}}^3 \\ V=\frac{1}{3}h{S}_1 \\ {S}_1=3\cdot V/h=3\cdot 1000/30=100{\text{cm}}^2 \\ {S}_1=a^2 \\ a=\sqrt{S_1}=\sqrt{100}=10\text{cm} \end{gathered}$$

$$\begin{gathered} h_2=\sqrt{h^2+(a/2{)}^2}=\sqrt{30^2+(10/2{)}^2}=5\sqrt{37}\text{cm}\doteq 30.4138\text{cm} \\ {S}_2=\frac{a\cdot h_2}{2}=\frac{10\cdot 30.4138}{2}=25\sqrt{37}{\text{cm}}^2\doteq 152.0691{\text{cm}}^2 \\ S=S_1+4\cdot S_2=100+4\cdot 152.0691=708.2763{\text{cm}}^2 \end{gathered}$$

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