Quadrilateral 5130

There is a regular quadrilateral pyramid with the base edge length a = 3 cm and with the length of the side edge h = 8 cm.
Please calculate its surface area and volume.

Correct answer:

S =  56.1487 cm2
V =  23.1409 cm3

Step-by-step explanation:

a=3 cm h=8 cm u=2 a=2 3=3 2 cm4.2426 cm v=h2(u/2)2=82(4.2426/2)27.7136 cm h2=v2+(a/2)2=7.71362+(3/2)27.8581 cm S1=a2=32=9 cm2 S2=a h2/2=3 7.8581/211.7872 cm2 S=S1+4 S2=9+4 11.7872=56.1487 cm2
V=S1 v/3=9 7.7136/3=23.1409 cm3

Did you find an error or inaccuracy? Feel free to write us. Thank you!

Tips for related online calculators
Tip: Our volume units converter will help you convert volume units.
The Pythagorean theorem is the base for the right triangle calculator.

You need to know the following knowledge to solve this word math problem:

We encourage you to watch this tutorial video on this math problem: video1   video2

Related math problems and questions: