Quadrilateral 5130

There is a regular quadrilateral pyramid with the base edge length a = 3 cm and with the length of the side edge h = 8 cm.
Please calculate its surface area and volume.

Correct answer:

S =  56.1487 cm2
V =  23.1409 cm3

Step-by-step explanation:

a=3 cm h=8 cm u=2 a=2 3=3 2 cm4.2426 cm v=h2(u/2)2=82(4.2426/2)27.7136 cm h2=v2+(a/2)2=7.71362+(3/2)27.8581 cm S1=a2=32=9 cm2 S2=a h2/2=3 7.8581/211.7872 cm2 S=S1+4 S2=9+4 11.7872=56.1487 cm2
V=S1 v/3=9 7.7136/3=23.1409 cm3



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