Quadrilateral 36061

In a regular quadrilateral pyramid, the length of the base edge is a = 8 cm, and the length of the side edge is h = 17 cm. Calculate the surface of the pyramid.

Correct answer:

S =  328.3634 cm2

Step-by-step explanation:

a=8 cm s=17 cm  u2=a2+a2  u=2 a=2 8=8 2 cm11.3137 cm  h2+(u/2)2=s2  h=s2(u/2)2=172(11.3137/2)2=257 cm16.0312 cm  S1=a2=82=64 cm2 h2=h2+(a/2)2=16.03122+(8/2)2=273 cm16.5227 cm S2=2a h2=28 16.5227=4 273 cm266.0908 cm2  S=S1+4 S2=64+4 66.0908=328.3634 cm2

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