The regular quadrangular prism has a base edge a = 7.1 cm and side edge = 18.2 cm long. Calculate its volume and surface area.

Result

V =  917.462 cm3
S =  617.7 cm2

#### Solution:

$a=7.1 \ \text{cm} \ \\ c=18.2 \ \text{cm} \ \\ S_{1}=a^2=7.1^2=\dfrac{ 5041 }{ 100 }=50.41 \ \text{cm}^2 \ \\ V=S_{1} \cdot \ c=50.41 \cdot \ 18.2=917.462 \ \text{cm}^3$
$S=2 \cdot \ S_{1}+4 \cdot \ a \cdot \ c=2 \cdot \ 50.41+4 \cdot \ 7.1 \cdot \ 18.2=\dfrac{ 6177 }{ 10 }=617.7 \ \text{cm}^2$

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