Pyramid 4sides

Calculate the volume and the surface of a regular quadrangular pyramid when the edge of the base is 4 cm long and the height of the pyramid is 7 cm.

Correct result:

V =  37.3333 cm3
S =  74.2409 cm2

Solution:

a=4 cm h=7 cm  S1=a2=42=16 cm2  V=S1⋅ h/3=16⋅ 7/3=1123=37.3333 cm3
h2=h2+(a/2)2=72+(4/2)2=53 cm≐7.2801 cm S2=a⋅ h2/2=4⋅ 7.2801/2=2 53 cm2≐14.5602 cm2  S=S1+4⋅ S2=16+4⋅ 14.5602=74.2409 cm2

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