Quadrilateral 83272

Calculate the surface area and volume of a regular quadrilateral pyramid whose base edge is 5 cm long and whose height is 10 cm.

Correct answer:

V =  83.3333 cm3
S =  128.0776 cm2

Step-by-step explanation:

a=5 cm h=10 cm  S1=a2=52=25 cm2  V=31 S1 h=31 25 10=83.3333 cm3
h2=h2+(a/2)2=102+(5/2)210.3078 cm  S2=2a h2=25 10.307825.7694 cm2  S=S1+4 S2=25+4 25.7694=128.0776 cm2

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