Quadrilateral 8220

Calculate the volume of a regular quadrilateral pyramid, whose wall height is w = 12 cm and the edge of the base is a = 5 cm.

Correct answer:

V =  97.8058 cm3

Step-by-step explanation:

w=12 cm a=5 cm  h=w2(a/2)2=122(5/2)211.7367 cm  S1=a2=52=25 cm2  V=31 S1 h=31 25 11.7367=97.8058 cm3

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