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Calculate the surface of a regular quadrilateral prism whose base edge is 2.4dm and the height of the prism is 38cm.

Result

S =  4800 cm2

Solution:

a=2.4 dm→cm=2.4⋅ 10 cm=24 cm c=38 cm  S=2⋅ a2+4⋅ a⋅ c=2⋅ 242+4⋅ 24⋅ 38=4800 cm2a=2.4 \ dm \rightarrow cm=2.4 \cdot \ 10 \ cm=24 \ cm \ \\ c=38 \ \text{cm} \ \\ \ \\ S=2 \cdot \ a^2 + 4 \cdot \ a \cdot \ c=2 \cdot \ 24^2 + 4 \cdot \ 24 \cdot \ 38=4800 \ \text{cm}^2

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