Triangular 46641

The regular triangular pyramid ABCDV has a length of the base edge a = 8 cm and a height of 7 cm. Calculate the surface area and volume of the pyramid

Correct answer:

V =  64.6632 cm3
S =  116.1662 cm2

Step-by-step explanation:

a=8 cm h=7 cm  h2=a2(a/2)2=82(8/2)2=4 3 cm6.9282 cm h12=h2+(h2/3)2 h1=h2+(h2/3)2=72+(6.9282/3)27.3711 cm  S1=a h1/2=8 7.3711/229.4845 cm2 S2=43 a2=43 82=16 3 cm227.7128 cm2  V=31 S2 h=31 27.7128 7=64.6632 cm3
S=3 S1+S2=3 29.4845+27.7128=116.1662 cm2

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