Quadrilateral 40551

Find the volume and surface area of ​​a regular quadrilateral pyramid ABCDV if its leading edge has a length a = 10 cm and a body height h = 12 cm.

Correct answer:

V =  400 cm3
S =  360 cm2

Step-by-step explanation:

a=10 cm h=12 cm  S1=a2=102=100 cm2  V=31 S1 h=31 100 12=400 cm3
h2=h2+(a/2)2=122+(10/2)2=13 cm S2=21 a h2=21 10 13=65 cm2  S=S1+4 S2=100+4 65=360 cm2

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