Regular quadrilateral pyramid

Find the surface area of a regular quadrilateral pyramid if for its volume V and body height v and the base edge a applies:
V = 2.8 m ^ 3, v = 2.1 m

Correct answer:

S =  13.3038 m2

Step-by-step explanation:

V=2.8 m3 v=2.1 m  V=31 S1 v  S1=3 V/v=3 2.8/2.1=4 m2  S1=a2  a=S1=4=2 m  h2=v2+(a/2)2=2.12+(2/2)22.3259 m  S2=2a h2=22 2.32592.3259 m2  S=S1+4 S2=4+4 2.3259=13.3038 m2



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