Pyramid - angle

Calculate the surface of regular quadrangular pyramid whose base edge measured 6 cm and the deviation from the plane of the side wall plane of the base is 50 degrees.

Correct result:

S =  92.0061 cm2

Solution:

h=(a/2)tan50=3.575 cm h2=h2+(a/2)2=4.667 cm S1=ah2/2=14.001 S=4S1+a2=92.0061 cm2



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