Regular quadrangular pyramid

How many square meters are needed to cover the shape of a regular quadrangular pyramid base edge 10 meters if the deviation lateral edges from the base plane are 68°? Calculate waste 10%.

Correct answer:

S =  400.4379 m2

Step-by-step explanation:

a=10 m α=68 ° q=10%=1+10100=1.1  u=2 a=2 10=10 2 m14.1421 m tanα=h:(u/2)  h=u/2 tanα°=u/2 tan68° =14.1421/2 tan68° =14.1421/2 2.475087=17.50151 m w2=h2+(a/2)2  w=h2+(a/2)2=17.50152+(10/2)218.2017 m  S1=a w2=10 18.2017291.0086 m2  S=4 S1 q=4 91.0086 1.1=400.4379 m2



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