House roof

The roof of the house has the shape of a regular quadrangular pyramid with a base edge 17 m. How many m2 is needed to cover roof if roof pitch is 57° and we calculate 11% of waste, connections and overlapping of area roof?

Correct answer:

S =  589 m2

Step-by-step explanation:

a=17 m cos57=a/2h=17/2h h=172cos57=15.61 m  S1=12ah=121715.61=132.685 m2  S=4S1(1+11100)=a2cos57=4132.6851.11=589 m2



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