House roof

The roof of the house has the shape of a regular quadrangular pyramid with a base edge 17 m. How much m2 is needed to cover the roof if the roof pitch is 57° and we calculate 11% of waste, connections, and overlapping of area roof?

Correct answer:

S =  589 m2

Step-by-step explanation:

a=17 m cos57=ha/2=h17/2 h=2cos5717=15.61 m  S1=21ah=211715.61=132.685 m2  S=4S1(1+10011)=cos57a2=4132.6851.11=589 m2

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