Quadrilateral 23701

We know the base diagonal length of u = 4 cm in a regular quadrilateral pyramid. The height of the pyramid is v = 5cm. Calculate the size of the side edge and the base edge of the pyramid.

Correct answer:

a =  2.8284 cm
s =  5.3852 cm

Step-by-step explanation:

u=4 cm v=5 cm  a2+a2=u2  a=u/2=4/2=2 2=2.8284 cm
s2=(u/2)2+v2=(4/2)2+52=29  s=(u/2)2+v2=(4/2)2+52=29=5.3852 cm

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