Regular triangular pyramid

Calculate the volume and surface area of the regular triangular pyramid and the height of the pyramid is 12 centimeters, the bottom edge has 4 centimeters and the height of the side wall is 12 centimeters

Result

V =  96 cm3
S =  96 cm2

Solution:

h=12 cm a=4 cm h2=12 cm  S1=a h2/2=4 12/2=24 cm2  V=13 S1 h=13 24 12=96 cm3h=12 \ \text{cm} \ \\ a=4 \ \text{cm} \ \\ h_{2}=12 \ \text{cm} \ \\ \ \\ S_{1}=a \cdot \ h_{2}/2=4 \cdot \ 12/2=24 \ \text{cm}^2 \ \\ \ \\ V=\dfrac{ 1 }{ 3 } \cdot \ S_{1} \cdot \ h=\dfrac{ 1 }{ 3 } \cdot \ 24 \cdot \ 12=96 \ \text{cm}^3
S=4 S1=4 24=96 cm2S=4 \cdot \ S_{1}=4 \cdot \ 24=96 \ \text{cm}^2



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