Triangular prism

Calculate the surface of a regular triangular prism with a bottom edge 8 of a length of 5 meters and an appropriate height of 60 meters and prism height is 1 whole 4 meters.

Correct result:

S =  545.7 m²

Solution:

$$\begin{gathered} a=8.5\text{ m } \\ v=60\text{ m } \\ {S}_1=a\cdot v\mathrm{/}2=8.5\cdot 60\mathrm{/}2=255{\text{m}}^2 \\ h=1.4\text{ m } \\ o=3\cdot a=3\cdot 8.5={\displaystyle \frac{51}{2}}=25.5\text{ m } \\ S=2\cdot S_1+o\cdot h=2\cdot 255+25.5\cdot 1.4={\displaystyle \frac{5457}{10}}={\displaystyle \frac{5457}{10}}{\text{m}}^2=545.7{\text{m}}^2 \end{gathered}$$

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