Triangular prism

Calculate the surface of a regular triangular prism with a bottom edge 8 of a length of 5 meters and an appropriate height of 60 meters and prism height is 1 whole 4 meters.

Result

S =  545.7 m2

Solution:

a=8.5 m v=60 m  S1=a⋅ v/2=8.5⋅ 60/2=255 m2 h=1.4 m  o=3⋅ a=3⋅ 8.5=512=25.5 m  S=2⋅ S1+o⋅ h=2⋅ 255+25.5⋅ 1.4=545710=545.7 m2a=8.5 \ \text{m} \ \\ v=60 \ \text{m} \ \\ \ \\ S_{ 1 }=a \cdot \ v/2=8.5 \cdot \ 60/2=255 \ \text{m}^2 \ \\ h=1.4 \ \text{m} \ \\ \ \\ o=3 \cdot \ a=3 \cdot \ 8.5=\dfrac{ 51 }{ 2 }=25.5 \ \text{m} \ \\ \ \\ S=2 \cdot \ S_{ 1 } + o \cdot \ h=2 \cdot \ 255 + 25.5 \cdot \ 1.4=\dfrac{ 5457 }{ 10 }=545.7 \ \text{m}^2

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