Regular triangular prism

Calculate the surface area of body of regular triangular prism, when the length of its base edge is 6.5 cm and height 0.2 m.

Result

S =  390 cm2

Solution:

a=6.5 h=0.2 100=20 h2=3/2 a=3/2 6.55.6292 S2=a h=6.5 20=130 S=3 S2=3 130=390 cm2a=6.5 \ \\ h=0.2 \cdot \ 100=20 \ \\ h_{2}=\sqrt{ 3 } / 2 \cdot \ a=\sqrt{ 3 } / 2 \cdot \ 6.5 \doteq 5.6292 \ \\ S_{2}=a \cdot \ h=6.5 \cdot \ 20=130 \ \\ S=3 \cdot \ S_{2}=3 \cdot \ 130=390 \ \text{cm}^2



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