Triangular prism

The regular triangular prism has a base edge of 8.6 dm and a height of 1.5 m.
Finf its volume and surface area.

Correct result:

V =  480.3843 dm3
S =  451.0512 dm2

Solution:

a=8.6 dm h=1.5 m→ dm=1.5⋅ 10  dm=15 dm  S1=34⋅ a2=34⋅ 8.62≐32.0256 dm2 V=S1⋅ h=32.0256⋅ 15=480.3843 dm3
S=3⋅ a⋅ h+2⋅ S1=3⋅ 8.6⋅ 15+2⋅ 32.0256=451.0512 dm2

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