Triangular prism

The regular triangular prism has a base edge of 8.6 dm and a height of 1.5 m.
Finf its volume and surface area.

Correct answer:

V =  480.3843 dm³
S =  451.0512 dm²

Step-by-step explanation:

$$\begin{gathered} a=8.6\text{ dm } \\ h=1.5\text{ m}\to \text{ dm}=1.5\cdot 10\text{ dm}=15\text{ dm } \\ {S}_1={\displaystyle \frac{\sqrt{3}}{4}}\cdot a^2={\displaystyle \frac{\sqrt{3}}{4}}\cdot 8.6^2\doteq 32.0256{\text{dm}}^2 \\ V=S_1\cdot h=32.0256\cdot 15=480.3843{\text{dm}}^3 \end{gathered}$$

$S=3\cdot a\cdot h+2\cdot S_1=3\cdot 8.6\cdot 15+2\cdot 32.0256=451.0512{\text{dm}}^2$

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