Quadrilateral pyramid,

A quadrilateral pyramid, which has a rectangular base with dimensions of 24 cm, 13 cm. The height of the pyramid is 18cm.
Calculate
1/the area of the base
2/casing area
3/pyramid surface
4/volume of the pyramid

Correct result:

S1 =  312 cm2
S =  740.5368 cm2
S4 =  1052.5368 cm2
V =  1872 cm3

Solution:

h=18 cm a=24 cm b=13 cm  S1=a b=24 13=312 cm2
h1=h2+(b/2)2=182+(13/2)219.1377 cm h2=h2+(a/2)2=182+(24/2)2=6 13 cm21.6333 cm  S2=a h12=24 19.13772=6 1465 cm2229.6519 cm2 S3=b h22=13 21.63332=39 13 cm2140.6165 cm2  S=2 S2+2 S3=2 229.6519+2 140.6165=740.5368 cm2
S4=S+S1=740.5368+312=1052.5368 cm2
V=13 S1 h=13 312 18=1872 cm3



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