Quadrilateral pyramid

Calculate the surface of a quadrilateral pyramid, which has a rectangular base with dimensions a = 8 cm, b = 6 cm and height H = 10 cm.

Correct result:

S =  196.1444 cm2

Solution:

h=10 cm a=8 cm b=6 cm  h1=h2+(b/2)2=102+(6/2)2=109 cm≐10.4403 cm h2=h2+(a/2)2=102+(8/2)2=2 29 cm≐10.7703 cm  S1=a⋅ h12=8⋅ 10.44032=4 109 cm2≐41.7612 cm2 S2=b⋅ h22=6⋅ 10.77032=6 29 cm2≐32.311 cm2  S=2⋅ S1+2⋅ S2+a⋅ b=2⋅ 41.7612+2⋅ 32.311+8⋅ 6=196.1444 cm2

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