Quadrilateral pyramid

Calculate the surface of a quadrilateral pyramid, which has a rectangular base with dimensions a = 8 cm, b = 6 cm and height H = 10 cm.

Correct result:

S =  196.1444 cm2

Solution:

h=10 cm a=8 cm b=6 cm  h1=h2+(b/2)2=102+(6/2)2=109 cm10.4403 cm h2=h2+(a/2)2=102+(8/2)2=2 29 cm10.7703 cm  S1=a h12=8 10.44032=4 109 cm241.7612 cm2 S2=b h22=6 10.77032=6 29 cm232.311 cm2  S=2 S1+2 S2+a b=2 41.7612+2 32.311+8 6=196.1444 cm2



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