Calculate the volume of a quadrilateral pyramid, the base of which has the shape of a rectangle with dimensions a = 6cm, b = 4cm and height v = 11cm

Correct result:

V =  88 cm3

#### Solution:

$a=6 \ \text{cm} \ \\ b=4 \ \text{cm} \ \\ v=11 \ \text{cm} \ \\ \ \\ S=a \cdot \ b=6 \cdot \ 4=24 \ \text{cm}^2 \ \\ \ \\ V=\dfrac{ 1 }{ 3 } \cdot \ S \cdot \ v=\dfrac{ 1 }{ 3 } \cdot \ 24 \cdot \ 11=88 \ \text{cm}^3$

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