The quadrilateral pyramid

The quadrilateral pyramid has a rectangular base of 24 cm x 3.2dm and a body height of 0.4m. Calculate its volume and surface area.

Correct result:

V =  10.24 dm3
S =  31.3831 dm2

Solution:

a=24 cm dm=24/10  dm=2.4 dm b=3.2 dm h=0.4 m dm=0.4 10  dm=4 dm  S1=a b=2.4 3.2=19225=7.68 dm2  V=13 S1 h=13 7.68 4=25625=25625 dm3=10.24 dm3
s2=h2+(a/2)2=42+(2.4/2)24.1761 dm s3=h2+(b/2)2=42+(3.2/2)24.3081 dm  S2=a s32=2.4 4.308125.1698 dm2 S3=b s22=3.2 4.176126.6818 dm2  S=S1+2 S2+2 S3=7.68+2 5.1698+2 6.6818=31.3831 dm2



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