Tetrahedral pyramid

Calculate the volume and surface area of a regular tetrahedral pyramid, its height is $b cm and the length of the edges of the base is 6 cm.

Correct result:

S =  196.1 cm2
V =  156 cm3

Solution:

a=6 cm h=13 cm s=h2+(a/2)2=132+(6/2)2=178 cm13.3417 cm S1=a s/2=6 13.3417/2=3 178 cm240.025 cm2  S=a2+4 S1=62+4 40.025=196.1 cm2
V=13 a2 h=13 62 13=156 cm3



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