Truncated pyramid

Find the volume of a regular 4-sided truncated pyramid if a1 = 14 cm, a2 = 8 cm and the angle that the side wall with the base is 42 degrees

Correct result:

V =  334.9503 cm3

Solution:

a1=14 cm a2=8 cm α=42 tanα=h1:(a2/2) tanα=h2:(a2/2)  h1=a1/2 tan(α)=14/2 tan(42)=6.30283 cm h2=a2/2 tan(α)=8/2 tan(42)=3.60162 cm  S1=a12=142=196 cm2 S2=a22=82=64 cm2  V1=13 S1 h1=13 196 6.3028411.7848 cm3 V2=13 S2 h2=13 64 3.601676.8345 cm3  V=V1V2=411.784876.8345=334.9503 cm3



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