Quadrilateral 5814

Calculate the surface area and volume of a regular quadrilateral truncated pyramid if the edges of the base are 87 cm and 64 cm and the wall height is 49 cm.

Correct answer:

V =  273610.6227 cm3
S =  26463 cm2

Step-by-step explanation:

a=87 cm b=64 cm s=49 cm  x=(ab)/2=(8764)/2=223=11.5 cm h=s2x2=49211.5247.6314 cm  S1=a2=872=7569 cm2 S2=b2=642=4096 cm2  V=h/3 (S1+S1 S2+S2)=47.6314/3 (7569+7569 4096+4096)=273610.6227 cm3=2.736105 cm3
S3=(a+b) s/2=(87+64) 49/2=27399=3699.5 cm2 S=S1+S2+4 S3=S1+S2+4 27399=7569+4096+4 3699.5=26463 cm2



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