Truncated pyramid

The concrete pedestal in a regular quadrilateral truncated pyramid has a height of 12 cm; the pedestal edges have lengths of 2.4 and 1.6 dm. Calculate the surface of the base.

Correct answer:

S =  1843.9289 cm2

Step-by-step explanation:

h=12 cm a=2.4 dm cm=2.4 10  cm=24 cm b=1.6 dm cm=1.6 10  cm=16 cm  S1=a2=242=576 cm2 S2=b2=162=256 cm2  x=a/2b/2=24/216/2=4 cm h2=x2+h2=42+122=4 10 cm12.6491 cm  S3=2a+b h2=224+16 12.6491=80 10 cm2252.9822 cm2  S=S1+S2+4 S3=576+256+4 252.9822=1843.9289 cm2

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