Truncated pyramid

The truncated regular quadrilateral pyramid has a volume of 74 cm3, a height v = 6 cm, and an area of the lower base 15 cm2 greater than the upper base's content. Calculate the area of the upper base.

Correct answer:

S1 =  5.6185 cm2

Step-by-step explanation:

V=74 cm3 v=6 cm S2=S1+15  V=v3 (S1+S1 S2+S2) 3 V/v=S1+S1 (S1+15)+S1+15 3 V/v15=2 S1+S1 (S1+15)  S1=15 v24 v2 V275 v4+4 v V2 v2=15 624 62 74275 64+4 6 742 625.6185 cm2   Verifying Solution:  S2=S1+15=5.6185+1520.6185 cm2  V2=v3 (S1+S1 S2+S2)=63 (5.6185+5.6185 20.6185+20.6185)=74 cm3



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