Quadrilateral 8109

The regular quadrilateral pyramid has a base diagonal of 5√2 cm, and the side edges are 12√2 cm long. Calculate the height of the pyramid and its surface.

Correct answer:

h =  16.5982 cm
S =  192.8541 cm2

Step-by-step explanation:

u1=5 2=5 2 cm7.0711 cm s=12 2=12 2 cm16.9706 cm  a=u1/2=7.0711/2=5 cm  h=s2(u1/2)2=16.97062(7.0711/2)2=16.5982 cm
S1=a2=52=25 cm2 h2=s2(a/2)2=16.97062(5/2)216.7854 cm  S2=2a h2=25 16.785441.9635 cm2  S=S1+4 S2=25+4 41.9635=192.8541 cm2

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