Park fountain percentage

In the park, with an area of 1413 m², there is a circular fountain with a diameter of 6 m. What percentage of the park does the fountain occupy?

Final Answer:

p =  2.001 %

Step-by-step explanation:

$$\begin{gathered} D=6\text{m} \\ r=D/2=6/2=3\text{m} \\ {S}_1=\pi \cdot r^2=3.1416\cdot 3^2\doteq 28.2743{\text{m}}^2 \\ {S}_2=1413{\text{m}}^2 \\ p=100\cdot \frac{S_1}{S_2}=100\cdot \frac{28.2743}{1413}=2.001\% \end{gathered}$$

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