Square diagonal

Calculate the length of the square diagonal if the perimeter is 476 cm.

Result

d =  168.29 cm

Solution:

o=476 cm  o=4a  a=o/4=476/4=119 cm  d2=a2+a2=1192+1192=28322  d=2⋅ a=2⋅ 119=119 2≐168.2914=168.29  cm o = 476 \ cm \ \\ \ \\ o = 4a \ \\ \ \\ a = o/4 = 476/4 = 119 \ cm \ \\ \ \\ d^2 = a^2 + a^2 = 119^2 + 119^2 = 28322 \ \\ \ \\ d = \sqrt{ 2 } \cdot \ a = \sqrt{ 2 } \cdot \ 119 = 119 \ \sqrt{ 2 } \doteq 168.2914 = 168.29 \ \text{ cm }

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