Octahedron in a cube

The largest octahedron that can be placed inside a cubical box with sides equal to 72?

Correct answer:

b =  88.1816

Step-by-step explanation:

a=72 d1=3 a=3 72=72 3124.7077  D=d1=124.7077=72 3124.7077  r=D/2=124.7077/2=36 362.3538  r=22 b  b=2 r/2=2 62.3538/2=36 6=88.1816

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