True or false?

Which of the following is true?

A three and three ninths plus seven and six elevenths equals ten and eighty seven ninety ninths
B two and three eighths plus six and four fifths equals eight and twelve fourtieths
C three and three sevenths plus four and two thirds equals seven and two twenty ones
D four and five sixths plus five sevenths equals nine and ten thirteenths

Result

A=

Yes

No

B=

Yes

No

C=

Yes

No

D=

Yes

No

Step-by-step explanation:

$$\begin{gathered} a_1=3+\frac{3}{9}+7+\frac{6}{11}=\frac{359}{33}=10\frac{29}{33}\doteq 10.8788 \\ {a}_2=10\frac{87}{99}=10+\frac{87}{99}=\frac{10\cdot 99+87}{99}=\frac{1077}{99}=\frac{359}{33}=10\frac{29}{33}\doteq 10.8788 \\ {a}_1=a_2 \\ A=1 \end{gathered}$$

$$\begin{gathered} b_1=2\frac{3}{8}+6\frac{4}{5}=9.175 \\ {b}_2=8\frac{12}{14}=8+\frac{12}{14}=\frac{8\cdot 14+12}{14}=\frac{124}{14}=\frac{62}{7}=8\frac{6}{7}\doteq 8.8571 \\ {b}_1\ne b_2 \\ B=0 \end{gathered}$$

$$\begin{gathered} c_1=3\frac{3}{7}+4\frac{2}{3}\doteq 8.0952 \\ {c}_2=7\frac{2}{21}=7+\frac{2}{21}=\frac{7\cdot 21+2}{21}=\frac{149}{21}\doteq 7.0952 \\ {c}_1\ne c_2 \\ C=0 \end{gathered}$$

$$\begin{gathered} d_1=4\frac{5}{6}+\frac{5}{7}=\frac{233}{42}=5\frac{23}{42}\doteq 5.5476 \\ {d}_2=9\frac{10}{13}=9+\frac{10}{13}=\frac{9\cdot 13+10}{13}=\frac{127}{13}\doteq 9.7692 \\ {d}_1\ne d_2 \\ D=0 \end{gathered}$$

Try another example