How many ways can we choose 5 pcs of salami if we have 6 types of salami for 10 pieces and one type for 4 pieces?

Correct answer:

x =  461

Step-by-step explanation:

C5(10)=(105)=10!5!(105)!=10987654321=252 C5(9)=(95)=9!5!(95)!=98764321=126 C5(8)=(85)=8!5!(85)!=876321=56 C5(7)=(75)=7!5!(75)!=7621=21 C5(6)=(65)=6!5!(65)!=61=6 k=5 x=(10k)+(9k)+(8k)+(7k)+(6k)=252+126+56+21+6=461

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Showing 5 comments:
I tried using (1/120) as a base to multiply the spaces 1/5 but then I end up with too many to multiply

It gets to a really small number!

This question is very unclear. choosing 5 pieces from 6 types for 10 pieces and 1 type for 4 pieces doesn't even make sense. How do we unpack this question?

Math student
My answer is 462
C(7,5) = 11!/ (5![6!) = 462

1 year ago  1 Like
Math student
Answer should be 461, since we have to subtract the selection where we selected 0,0,0,0,0,0,5 which isn't possible because the last type has only 4 pieces.

1 year ago  1 Like

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