# Chocolates

In the market have 3 kinds of chocolates.

How many ways can we buy 14 chocolates?

Correct result:

n =  120

#### Solution:

$n={C}_{14}^{\mathrm{\prime }3}={C}_{14}\left(16\right)=\left(\genfrac{}{}{0px}{}{16}{14}\right)=\frac{16!}{14!\left(16-14\right)!}=\frac{16\cdot 15}{2\cdot 1}=120$

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