# Chase

Paul travel at 60 km/h. After 18 km ride found that he forgot an important book. His brother Thomas behind him carrying it. How fast must Thomas go to catch up with Paul in 31 minutes?

Result

v2 =  94.8 km/h

#### Solution:

$s_1 = s_2 \ \\ 60\cdot ( \dfrac{ 18}{ 60} + \dfrac{ 31}{60}) = v_2 \cdot \dfrac{ 31 }{ 60} \ \\ v_2=94.8 \ \text { km/h }$

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