A biker

A biker traveled from city A to city B via city C with a uniform speed of 52 km/h. He then returned directly to city A with a uniform speed of 89 km/h. Find, in minutes, the total time of his whole journey to two decimal places.

City distance A from B is 50 km, B from C is 40 km, and C from A is 30 km.

Correct answer:

t =  124.0709 min

Step-by-step explanation:

v1=52 km/h v2=89 km/h  c=50 km a=40 km b=30 km  s1=c+a=50+40=90 km s2=b=30 km  t1=s1/v1=90/52=26451.7308 h t2=s2/v2=30/89=89300.3371 h  t3=t1+t2=1.7308+0.33712.0678 h  t=t3 min=t3 60  min=2.0678 60  min=124.071 min=124.0709 min



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