Bus vs. train

Bus started from point A 10 minutes before the train started from the same place. The bus went an average speed of 49 km/h, train 77 km/h.
To point B train and bus arrived simultaneously.

Calculate time of train journey, if train and bus travelled the same distance.

Result

t =  17.5 min

Solution:

 s=v1(t+10)/60=v2t/60  49(t+10)=77t  t=49⋅1077−49=17.5 min \ \\ s = v_1 (t+10)/60 = v_2 t/60 \ \\ \ \\ 49 (t+10) = 77 t \ \\ \ \\ t = \dfrac{ 49\cdot 10}{ 77-49 } = 17.5 \ \text{min}

49 (t+10) = 77 t

28t = 490

t = 352 = 17.5

Calculated by our simple equation calculator.

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