Bus vs. train

The bus started from point A 10 minutes before the train started from the same place. The bus went an average speed of 49 km/h, train 77 km/h.
To point B train and bus arrived simultaneously.

Calculate the time of the train journey, if train and bus traveled the same distance.

Correct result:

t =  17.5 min

Solution:

$\ \\ s = v_1 (t+10)/60 = v_2 t/60 \ \\ \ \\ 49 (t+10) = 77 t \ \\ \ \\ t = \dfrac{ 49\cdot 10}{ 77-49 } = 17.5 \ \text{min}$

49 (t+10) = 77 t

49•(t+10) = 77•t

28t = 490

t = 35/2 = 17.5

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