Bus vs. train

The bus started from point A 10 minutes before the train started from the same place. The bus went an average speed of 49 km/h, train 77 km/h.
To point B train and bus arrived simultaneously.

Calculate the time of the train journey, if train and bus traveled the same distance.

Correct result:

t =  17.5 min

Solution:

$$\begin{gathered} s=v_1(t+10)\mathrm{/}60=v_{2}t\mathrm{/}60 \\ 49(t+10)=77t \\ t={\displaystyle \frac{49\cdot 10}{77-49}}=17.5\text{ min} \end{gathered}$$

49 (t+10) = 77 t

49•(t+10) = 77•t

28t = 490

t = 35/2 = 17.5

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