# Pedestrian

Dana started at 10:00 from the point A to point B. These points are distant 12 km. Determine how fast Daniel went when the place B arrived at 11:54. Speed express in km/h.

Result

v =  6.316 km/h

#### Solution:

$s=12 \ \\ t=(11+54/60)-10=\dfrac{ 19 }{ 10 }=1.9 \ \\ v=s/t=12/1.9 \doteq \dfrac{ 120 }{ 19 } \doteq 6.3158 \doteq 6.316 \ \text{km/h}$

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